63x^2-256=0

Solution for 63x^2-256=0 equation:

63x^2-256=0

a = 63; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·63·(-256)
Δ = 64512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{64512}=\sqrt{9216*7}=\sqrt{9216}*\sqrt{7}=96\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96\sqrt{7}}{2*63}=\frac{0-96\sqrt{7}}{126}
=-\frac{96\sqrt{7}}{126}
=-\frac{16\sqrt{7}}{21}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96\sqrt{7}}{2*63}=\frac{0+96\sqrt{7}}{126}
=\frac{96\sqrt{7}}{126}
=\frac{16\sqrt{7}}{21}
$